What is the approximate voltage drop across the 20-ohm coil in the series arrangement described above?

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Multiple Choice

What is the approximate voltage drop across the 20-ohm coil in the series arrangement described above?

Explanation:
In a series circuit, the same current flows through every component, and the voltage across each part is proportional to its resistance. The voltage across the 20-ohm coil is found by multiplying the circuit current by its resistance: V = I × 20. The current in this setup is determined by the total resistance and the 24 V supply. If the total resistance is about 220 ohms, the current is roughly 0.109 A, giving a voltage drop across the 20-ohm coil of 0.109 × 20 ≈ 2.18 V. The remaining voltage (about 21.82 V) drops across the other components in the series. Therefore, the approximate voltage drop across the 20-ohm coil is about 2.18 V.

In a series circuit, the same current flows through every component, and the voltage across each part is proportional to its resistance. The voltage across the 20-ohm coil is found by multiplying the circuit current by its resistance: V = I × 20. The current in this setup is determined by the total resistance and the 24 V supply. If the total resistance is about 220 ohms, the current is roughly 0.109 A, giving a voltage drop across the 20-ohm coil of 0.109 × 20 ≈ 2.18 V. The remaining voltage (about 21.82 V) drops across the other components in the series. Therefore, the approximate voltage drop across the 20-ohm coil is about 2.18 V.

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